1992 United States presidential election in Delaware

1992 United States presidential election in Delaware

← 1988 November 3, 1992 1996 →
 
Nominee Bill Clinton George H. W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 3 0 0
Popular vote 126,054 102,313 59,213
Percentage 43.52% 35.33% 20.45%

County Results

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Delaware took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware was won by Governor Bill Clinton (D-Arkansas) with 43.52%% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.33%. Businessman Ross Perot (I-Texas) finished in third, with 20.45% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush. Clinton comfortably won Delaware by a margin of 8.19%. This was the last election where Delaware was a swing state, with the margin within 3% of the national vote. In 1996, the state would shift to the left, becoming a Democratic stronghold.[2]

As of the 2020 United States presidential election, this is the last time in which Kent County voted for the losing candidate.

  1. ^ Cite error: The named reference results was invoked but never defined (see the help page).
  2. ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 8, 2012.

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